Details
-
Improvement
-
Resolution: Done
-
Major - P3
-
None
-
None
-
mac osx
*Location*: http://docs.mongodb.org/manual/reference/sql-aggregation-comparison/
*User-Agent*: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_7_5) AppleWebKit/537.78.2 (KHTML, like Gecko) Version/6.1.6 Safari/537.78.2
*Screen Resolution*: 1920 x 1080
*repo*: docs
*source*: reference/sql-aggregation-comparison
mac osx *Location*: http://docs.mongodb.org/manual/reference/sql-aggregation-comparison/ *User-Agent*: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_7_5) AppleWebKit/537.78.2 (KHTML, like Gecko) Version/6.1.6 Safari/537.78.2 *Screen Resolution*: 1920 x 1080 *repo*: docs *source*: reference/sql-aggregation-comparison
Description
Document says the equivalent of select count
from orders is as under:
db.orders.aggregate( [
{
$group: {
_id: null,
count:
}
}
] )
My question is that db.orders.count() gives me the same answer. A lot simpler.