I write some code for run shell

var args = new EvalArgs

{ Args = Params.ToArray(), Code = js }

;
var result = mongoDb.Eval(args);
txtResult.Text = result.ToJson(MongoHelper.JsonWriterSettings);

When I run shell db.GroupTest.find({}); via C#.
the result looks like

{
"_mongo" :

{ "slaveOk" : false, "host" : "EMBEDDED" }

,
"_db" : {
"_mongo" :

{ "slaveOk" : false, "host" : "EMBEDDED" }

,
"_name" : "MongoBooster"
},
"_collection" : {
"_mongo" :

{ "slaveOk" : false, "host" : "EMBEDDED" }

,
"_db" : {
"_mongo" :

{ "slaveOk" : false, "host" : "EMBEDDED" }

,
"_name" : "MongoBooster"
},
"_shortName" : "GroupTest",
"_fullName" : "MongoBooster.GroupTest"
},
"_ns" : "MongoBooster.GroupTest",
"_query" : { },
"_fields" : null,
"_limit" : 0.0,
"_skip" : 0.0,
"_batchSize" : 0.0,
"_options" : 0.0,
"_cursor" : null,
"_numReturned" : 0.0,
"_special" : false
}

what I really want is the dataset records. How can I do it?Thank you.
The code below will return what I want,but , I want to get the result without use toArray() method,just like mongo.exe
var c = db.GroupTest.find({});
return c.toArray();