,"s":"D2", "c":"QUERY", "id":20961, "ctx":"conn149","msg":"Score formula","attr":{"formula":"score(1.5002) = baseScore(1) + productivity_((1 advances)/(1 numReads) = 0.5)_ + tieBreakers(0 noFetchBonus + 0.0001 noSortBonus + 0.0001 noIxisectBonus = 0.00020000000000000001)"}}

1/1=0.5，it is wrong。In fact， it is (0 + 1) / (1 + 1) = 0.5

in calculateProductivity func, add 1 to both the numerator and denominator, So we need to keep the results consistent